- #1
ChrisMC
- 17
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A uniform electric field of 1.0 N/C is set up by a uniform distribution of charge in the xy-plane. What is the electric field inside a metal ball placed 0.50 m above the xy-plane?
E= Fe/q
E=(kq1q2)/r^2
0= ((9x10^9)(1)(q2))/.5^2
q2= 0
does this sound right?
E= Fe/q
E=(kq1q2)/r^2
0= ((9x10^9)(1)(q2))/.5^2
q2= 0
does this sound right?