- #1
krv77
- 1
- 0
1. The problem is:
A vertical wall (5.9m x2.5m) in a house faces due east. A uniform electric field has a magnitude of 150 N/C. This field is parallel to the ground and points 35degrees north of east. What is the electric flux through the wall?
2. Homework Equations :
Electric flux is found by using E cos of angle between electric field and normal.
E= f/q
3. The Attempt at a Solution
Well, I tried it this way and don't think it is right.
E= 150 N/C
_______
(5.9 x 2.5m) x cos 35 degrees
I think the answer will be radially outward as oposed to inward, but I am not too sure.
The answer choices we were given are
A. 7.9 x 10*5 radially outward
B. 3.2 x 10*5 radially outward
C.1.4 x 10*6 ...inward
D. 5.9 x 10*5...inward
E. zero
I don't see how it would be zero, and I think I have narrowed it down to either A or B.
A vertical wall (5.9m x2.5m) in a house faces due east. A uniform electric field has a magnitude of 150 N/C. This field is parallel to the ground and points 35degrees north of east. What is the electric flux through the wall?
2. Homework Equations :
Electric flux is found by using E cos of angle between electric field and normal.
E= f/q
3. The Attempt at a Solution
Well, I tried it this way and don't think it is right.
E= 150 N/C
_______
(5.9 x 2.5m) x cos 35 degrees
I think the answer will be radially outward as oposed to inward, but I am not too sure.
The answer choices we were given are
A. 7.9 x 10*5 radially outward
B. 3.2 x 10*5 radially outward
C.1.4 x 10*6 ...inward
D. 5.9 x 10*5...inward
E. zero
I don't see how it would be zero, and I think I have narrowed it down to either A or B.
Last edited: