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Bigworldjust
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Homework Statement
An ammonia molecule (NH3) has a permanent electric dipole moment 5.0 x 10^-30cm. A proton is 2.50nm from the molecule in the plane that bisects the dipole.
What is the electric force of the molecule on the proton?
Homework Equations
F = QE = eE_yj = (-kpe)/(d^3)j
The Attempt at a Solution
((9*10^9 N*m^2/C^2)(5.0*10^-30 C*m)(1.6*10^-19 C))/(2.5*10^-9)^3
This gives me an answer of 5.0*10^-13 N, but that seems to be wrong. Anyone know where I went wrong here? Thank you!