What is the electric potential energy of two electrons separated by 2.68 nm?

[breedb]

What is the electric potential energy in joules of two electrons separated by 2.68 nm?

 

[hage567]

So...what have you tried? What equation do you think you need?

 

[ogb p]

Electric potential energy is a measure of the potential energy stored in a system due to the presence of electric charges. In this case, we are considering the electric potential energy between two electrons separated by a distance of 2.68 nm.

To calculate the electric potential energy, we can use the formula:

U = ke * (q1 * q2) / r

Where U is the electric potential energy, ke is the Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges of the two electrons, and r is the distance between them.

Since both electrons have the same charge (1.602 x 10^-19 C), we can rewrite the formula as:

U = ke * (1.602 x 10^-19 C)^2 / 2.68 x 10^-9 m

Plugging in the values, we get:

U = (8.99 x 10^9 Nm^2/C^2) * (2.57 x 10^-38 C^2) / 2.68 x 10^-9 m

U = 2.57 x 10^-29 Nm / 2.68 x 10^-9 m

U = 9.59 x 10^-21 J

Therefore, the electric potential energy between two electrons separated by 2.68 nm is approximately 9.59 x 10^-21 joules. This value may seem small, but it is a significant amount of energy on the atomic scale.