- #1
oldspice1212
- 149
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A photon with wavelength lambda = 0.1050 nm is incident on an electron that is initially at rest. If the photon scatters at an angle of 60.0 degrees from its original direction, what are the magnitude and direction of the linear momentum of the electron just after the collision with the photon?
Hey guys, was wondering if someone could help me out with this, I understand I have to use conservation of momentum, so I have for x direction (I'll be using y for lambda here): h/y=h/y'+Pecos(theta)
so Pe =cos theta( h/y-h/y' ) but this seems to be wrong, I'm not sure why, I just need to understand why this isn't right, thanks.
Hey guys, was wondering if someone could help me out with this, I understand I have to use conservation of momentum, so I have for x direction (I'll be using y for lambda here): h/y=h/y'+Pecos(theta)
so Pe =cos theta( h/y-h/y' ) but this seems to be wrong, I'm not sure why, I just need to understand why this isn't right, thanks.