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ahazen
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Given: There are two parallel plates. The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The magnitude of the electric field between the plates is 100 kV/m. The plates each have an area of 2 × 10-3 m2, and the spacing between the plates is 6 × 10-3 m. There is no dielectric between the plates. Calculate the energy stored in the capacitor.
I found C is 2.95 x10^-12 by taking ((8.85x10^-12)(2 x10^-3))/(6x10^-3).
I know:
the electric field is uniform and that V=E*d
The potential difference is just the magnitude of the electric field times the distance you move in the electric field
When I try to solve for V or PE, I keep getting the Power of ten error.
Can someone please help me?
Thank you:)
I found C is 2.95 x10^-12 by taking ((8.85x10^-12)(2 x10^-3))/(6x10^-3).
I know:
the electric field is uniform and that V=E*d
The potential difference is just the magnitude of the electric field times the distance you move in the electric field
When I try to solve for V or PE, I keep getting the Power of ten error.
Can someone please help me?
Thank you:)