- #1
skies222
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Sorry to post another problem, but hey, the more the marrier, right?
maxima/minima problem
2)a cylinder, including top and bottom, is made from material which costs "x" dollars per square inch. Suppose there is an additional cost of fabrication given by "n" dollars per inch of the circumfrence of the top and bottom of the can. find an algerbraic equation whose solution would be he radius ,r, of the can of given volume, V, whose cost is a minimum.
* Do not have to solve equation, just find a algerbraic solution
I tried this one, and I think I may be overthinking it. Would the equation just consists of the volume of the cone (equalling the money for the material) plus the additional amount of the circumfrence of top and bottom (so two times the circumfrence) for the entire cost of the can?
Once again, thanks again!
Homework Statement
maxima/minima problem
2)a cylinder, including top and bottom, is made from material which costs "x" dollars per square inch. Suppose there is an additional cost of fabrication given by "n" dollars per inch of the circumfrence of the top and bottom of the can. find an algerbraic equation whose solution would be he radius ,r, of the can of given volume, V, whose cost is a minimum.
* Do not have to solve equation, just find a algerbraic solution
Homework Equations
The Attempt at a Solution
I tried this one, and I think I may be overthinking it. Would the equation just consists of the volume of the cone (equalling the money for the material) plus the additional amount of the circumfrence of top and bottom (so two times the circumfrence) for the entire cost of the can?
Once again, thanks again!