What is the Escape Speed Formula and How Do I Use It to Solve Problems?

In summary, the speaker is trying to find the potential energy of a 118.0-kg object at the surface of the earth, using the Earth's radius of 6.37E+6 m. They also mention not understanding the concept of escape speed and the equation for it, but eventually come to understand it as a way to calculate the kinetic energy needed for an object to escape to infinity.
  • #1
envscigrl
19
0
problem:
Taking the potential energy to be zero at infinite separation, find the potential energy of a 118.0-kg object at the surface of the earth. (Use 6.37E+6 m for the Earth's radius.)
I did this and got -7.374E09.
It then asks Find the escape speed for a body projected from this height.
I do not understand the concept of escape speed. In my book it gives this equation: sqrt 2gRe
It then goes on to solve the equation to be 11.2km/s.
How do I use this equation or the concept of escape speed to solve this problem.
Thanks for the help.
 
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  • #2
It's just the simplification of (1/2)mv^2=[G(Me)m]/(Re). For the object to escape to infinity, its kinetic energy must at least equal to its potential energy on the Earth because that much of work has to be done to bring the object to the infinity.
 
  • #3
Thank you very much that makes a lot of sense!
 

FAQ: What is the Escape Speed Formula and How Do I Use It to Solve Problems?

What is escape speed?

Escape speed is the minimum speed required for an object to escape the gravitational pull of a massive body, such as a planet or star. It is the speed at which the object will have enough kinetic energy to overcome the gravitational potential energy of the body.

Why is escape speed considered "weird"?

Escape speed is considered weird because it does not follow our intuitive understanding of gravity. We tend to think that the heavier an object is, the stronger its gravitational pull will be. However, escape speed is not directly related to the mass of the body, but rather to its size and density.

How is escape speed calculated?

Escape speed is calculated using the formula v = √(2GM/r), where v is the escape speed, G is the gravitational constant, M is the mass of the body, and r is the distance from the center of the body to the object. This formula applies to any massive body, as long as the object is starting from the surface of the body.

Can escape speed be exceeded?

Yes, escape speed can be exceeded. However, this would require an additional external force, such as a rocket engine, to be applied to the object. Without this additional force, the object will not be able to escape the gravitational pull of the body.

What are some real-life examples of escape speed?

An example of escape speed is the speed required for a rocket to leave Earth's orbit and travel to other planets. Another example is the speed required for a meteor to escape the gravitational pull of a planet and enter its atmosphere. The escape speed for Earth is approximately 11.2 km/s, while the escape speed for the Sun is about 617.5 km/s.

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