- #1
ParisSpart
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the random value X takes values 1,2,3... and has the X has geometric distribution with p=0.20 (This means that X can be interpreted as the time the first crown to repeated throws a coin coin lands heads with probability p.) what is the expected value E(X/X>=6)=?
i use this type : E(X/X>=6)=sum(k*P(X=k/X>=6))
but how i can estimate this> how i will find P(X=k and X>=6)=? and P(X>=6)=? where k=1,2,3...
i use this type : E(X/X>=6)=sum(k*P(X=k/X>=6))
but how i can estimate this> how i will find P(X=k and X>=6)=? and P(X>=6)=? where k=1,2,3...