What is the expression for Compton scattering angle in terms of t?

In summary, the question asks for the angle that the energy and momentum of the scattered photon and electron are equal. The problem appears to be quite advanced and requires algebra to solve. The intent of the problem is to find the angle that the energy and momentum of the scattered photons and electrons are equal, but the OP is not able to do so himself.
  • #1
jjson775
103
23
Homework Statement
A 0.880 MeV photon is scattered by a free electron initially at rest such that the scattering angle of the scattered electron equals that of the scattered photon. (a) Determine the angles theta and phi. (b) Determine the energy and momentum of the scattered photon. (c) Determine the kinetic energy and momentum of the scattered electron.
Relevant Equations
See below
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1615689602647.png
2C330813-F056-4C01-A522-33721781C646.jpeg
 
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  • #2
I don't follow what you are doing there. I wouldn't consider converting the energy of the photon from ##eV## to joules as a good start. How does that help?

The question says that the scattering angles are the same and asks you to find the angle. I can't see any attempt at finding this angle.

This problem looks quite advanced and certainly isn't an exercise in number crunching. I think you'll need a fair bit algebra for part (a).

Also, previously you said:

jjson775 said:
Thanks, I will give LaTeX a shot.

I think you should.
 
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  • #3
jjson775 said:
Homework Statement:: A 0.880 MeV photon is scattered by a free electron initially at rest such that the scattering angle of the scattered electron equals that of the scattered photon. (a) Determine the angles theta and phi. (b) Determine the energy and momentum of the scattered photon. (c) Determine the kinetic energy and momentum of the scattered electron.
Relevant Equations:: See below

For symmetrical scattering like this, you may use the equation: $$\cos\phi=\cos\theta=\frac{E_i+E_0}{E_i+2E_0}$$.

Source https://www.physicsforums.com/insights/massive-meets-massless-compton-scattering-revisited/
 
  • #4
neilparker62 said:
For symmetrical scattering like this, you may use the equation: $$\cos\phi=\cos\theta=\frac{E_i+E_0}{E_i+2E_0}$$.
It's homework and the above equation would not generally be supplied as a 'standard, ready-to-use' equation (but the OP should check this).

I'd guess the OP could either derive the above equation before using it, or solve the problem from first principles using conservation laws (messy algebra likely). I suspect the latter is what is expected.
 
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  • #5
PeroK said:
I don't follow what you are doing there. I wouldn't consider converting the energy of the photon from ##eV## to joules as a good start. How does that help?

The question says that the scattering angles are the same and asks you to find the angle. I can't see any attempt at finding this angle.

This problem looks quite advanced and certainly isn't an exercise in number crunching. I think you'll need a fair bit algebra for part (a).

Also, previously you said:
I think you should.
I did look at LaTeX but decided as a hobbyist, self studying, that I will stick with Nuten. I hope this isn’t too much of an inconvenience for the moderators whose feedback I appreciate very much.
 
  • #6
jjson775 said:
I did look at LaTeX but decided as a hobbyist, self studying, that I will stick with Nuten. I hope this isn’t too much of an inconvenience for the moderators whose feedback I appreciate very much.
The real issue for this problem is how you go about finding the common scattering angle. To do that, you need to manipulate the energy and momentum conservation laws and equations.

You need to write down the key equations and then solve for the required unknown quantities. Equations with symbols for energy and momentum are preferred.

Hint: you don't need Planck's constant for this. And, although you could use the Compton formula, I'm not sure it makes things any simpler. I suggest treating this like a standard scattering problem.
 
  • #7
Steve4Physics said:
It's homework and the above equation would not generally be supplied as a 'standard, ready-to-use' equation (but the OP should check this).

I'd guess the OP could either derive the above equation before using it, or solve the problem from first principles using conservation laws (messy algebra likely). I suspect the latter is what is expected.
I think the intent is to solve the problem with conservation laws which I won’t be able to do. I tried to solve the formula below that I found in a related thread but got stuck.
1615858119345.png
 
  • #8
jjson775 said:
I think the intent is to solve the problem with conservation laws which I won’t be able to do. I tried to solve the formula below that I found in a related thread but got stuck.
View attachment 279820
In general, you seem to be able to put numbers into a single equation. That means you need someone else to solve the problem for you and provide you with that single equation.

To solve the problem yourself you must combine and manipulate several equations to get the new equation you need. Looking at your homework posts in general, that doesn't seem to be something you do.

There's not a lot we can do to help until you learn to manipulate equations for yourself.
 
  • #9
Steve4Physics said:
It's homework and the above equation would not generally be supplied as a 'standard, ready-to-use' equation (but the OP should check this).

I'd guess the OP could either derive the above equation before using it, or solve the problem from first principles using conservation laws (messy algebra likely). I suspect the latter is what is expected.
Yes - perhaps I did too much of the work for the OP here and he would indeed have to show where the equation came from before using it. Digging around you don't seem to find much on the calculation of ##\phi## but a more general purpose equation which can easily be derived from the standard Compton scattering vector diagram is the following: $$ \tan\phi=\frac{E_2\sin\theta_d}{E_1-E_2\cos\theta_d} $$ where ##E_1## and ##E_2## are the energies of the incident and scattered photons respectively and ##\theta_d## is the angle of deflection.

Another point which has been emphasised in previous threads in that really the energy form of the Compton scattering equation should be recommended - ie: $$1-cos\theta_d=E_0\left(\frac{1}{E_2}-\frac{1}{E_1}\right)$$
 
  • #10
1616434185736.png


Let ##t=\tan\left(\frac{\theta}{2}\right)## and write everything in terms of t.
 

FAQ: What is the expression for Compton scattering angle in terms of t?

What is Compton scattering angle?

Compton scattering angle is the angle at which a photon is scattered after colliding with a free electron. It is a fundamental process in which the energy and momentum of the photon is transferred to the electron, resulting in a change in the photon's wavelength and direction.

What is the expression for the Compton scattering angle?

The expression for the Compton scattering angle is given by θ = arccos(1 - (λ'/λ)), where θ is the scattering angle, λ' is the scattered photon's wavelength, and λ is the incident photon's wavelength.

How is the Compton scattering angle related to the energy of the photon?

The Compton scattering angle is directly proportional to the energy of the photon. This means that as the energy of the photon increases, the scattering angle also increases.

Can the Compton scattering angle be negative?

No, the Compton scattering angle cannot be negative. It is always a positive value between 0 and 180 degrees.

What is the significance of the Compton scattering angle in physics?

The Compton scattering angle is an important concept in quantum mechanics and is used to understand the behavior of particles at the atomic level. It also has practical applications in fields such as medical imaging and materials science.

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