Absolutely. That is the way to go. The only question I have is, what exactly does the statement of the problem mean by the word, "negligible distance".?andrewkirk said:Calculate the work done on the particle by the force in moving it to distance d away from O. Then find the velocity at which the mass has that kinetic energy.
Ah! So the particle is moving effectively from 0 to d?andrewkirk said:In practice it means you can use zero as the lower limit for your integration. I expect the reason they said 'negligible distance' rather than 'start at O' is that usually when forces are symmetrically arranged around a point it's because there's a particle at that point, and two particles can't occupy the same point in classical phycics.
A force field is a physical phenomenon in which a particle experiences a force due to its position in space. This force can be caused by gravity, electromagnetic fields, or other types of forces.
A force field can change the direction and speed of a particle's movement. The particle will move in the direction of the net force acting on it, and its velocity will change in accordance with the laws of motion.
The final velocity of a particle in a force field can be calculated using the equation: V = U + at, where V is the final velocity, U is the initial velocity, a is the acceleration due to the force field, and t is the time elapsed.
The final velocity of a particle can be affected by the strength of the force field, the initial velocity of the particle, and the duration of the particle's exposure to the force field. Other factors such as the mass and shape of the particle may also play a role.
Yes, the final velocity of a particle can be zero if the net force acting on the particle is zero, or if the particle's initial velocity and acceleration due to the force field are equal in magnitude but opposite in direction.