rzlblrt417 said:Homework Statement
a ball hits a wall at 60 degrees from the wall and leaves the wall at 60 degrees.
v1 = 10 m/s
v2 = 10 m/s
m = 3.00 kg
t = 0.200s
Homework Equations
p = mvcos(angle)
J = p2 - p1
The Attempt at a Solution
p = (3.00)(10)(cos(60))
p1 = 15
p2 = 15
and that is as far as i can get. I am not sure how time plays into this. Any help is appreciated. I have the text in a few hours. Thank you
rzlblrt417 said:*by wall on the ball
sankalpmittal said:Got that ! Ok so what is p1 ? Or I mean momentum of the ball before striking the wall ?
Then you find out p2 or the momentum of ball after it stroke the wall.
What do you get ?
rzlblrt417 said:the same thing for p1 as p2?
sankalpmittal said:No p1 and p2 aren't same. Be careful regarding geometry.
Hint : see the image : http://postimage.org/image/qvnhzhnsl/
rzlblrt417 said:ok so then
p1 = (3.00)(10)cos(30)
p2 = (3.00)(10)cos(60)
so p2 - p1 = -14.133 so then it would just be 14.133N?
or is it sin(30) making it 14.5N
sankalpmittal said:Correct.
Right !
Nope. What about time t ?
From Newton's second law : F= Δp/Δt = p1-p2/t
Plug in it. What do you get ?
Do calculations properly. You got it wrong for p1-p2 also.
rzlblrt417 said:OH! ok so then after plugging everything in i got 71.6N!
The speed of each ball plays a significant role in determining the outcome of a collision. The faster a ball is moving, the greater its momentum and kinetic energy, which can result in a more forceful collision. This can lead to a larger change in direction or velocity for both balls involved.
In an elastic collision, both balls retain their original shapes and no kinetic energy is lost. This means that the total kinetic energy before and after the collision remains the same. In an inelastic collision, the balls may deform or stick together, and some kinetic energy is lost in the form of heat or sound. This results in a decrease in the total kinetic energy after the collision.
The angle of collision between two balls can greatly impact the resulting velocities. If the balls collide head-on, the final velocities will be equal but in opposite directions. However, if the collision occurs at an angle, the final velocities will be split into two components: one parallel to the line of collision and one perpendicular to it. The angle of collision also affects the amount of kinetic energy transferred between the balls.
Yes, in a perfectly elastic collision, two balls with different masses can have the same final velocity if the lighter ball has a higher initial velocity. This is because the kinetic energy transferred between the balls depends on their relative masses and velocities, rather than their individual masses.
Several factors can affect the outcome of a ball collision, including the masses, velocities, and angles of the balls involved, as well as the elasticity of the balls and the surface they are colliding on. Other external factors such as air resistance and friction can also play a role in determining the final outcome.