What is the Force Exerted by a Falling Rod on a Hinged Support?

[Chestermiller]

$$F_n=\frac{4Fr^3}{3L^3}\cos{\theta}$$ Thank you both for the input!

Good, except lose the r^3 and the L^3

 

[kuruman]

The moment of the drag force is $M=FL\cos{\theta}=\int_0^L{k'r^3dr}=k'\frac{L^4}{4}$

Question: Why is the upper limit of integration L? The drawing attached to post #16 shows the fluid extending only partially along the full length of the rod. Or is it just a drawing?

 

[Chestermiller]

Question: Why is the upper limit of integration L? The drawing attached to post #16 shows the fluid extending only partially along the full length of the rod. Or is it just a drawing?

That's not how I interpreted the diagram. I don't know what the correct interpretation is. Josh?

 

[member 428835]

Yea, my drawing is imperfect. Fluid is coming out of the entire triangular region.

 

[TSny]

The initial question posed was asking what force the hinge exerts on the ground.

There is no mention of the ground in the OP. Have you stated the problem word-for-word as given?

Not that I think I can contribute anything here, but I just wanted to understand the statement of the problem. I can't make any sense out of it whatsoever.