- #1
tnutty
- 326
- 1
Homework Statement
Find the area of the parallelogram with the vectices :
A(-2,1)
B(0,4)
C(4,2)
D(-2,1)
Homework Equations
This sections is about vectors, specifically crossproducts.
A = |a|(|b|sin(/theta) = |a x b|
- The length of the cross product a x b is equal to the area of the parallelogram determined
by a and b
The Attempt at a Solution
Instead of using the equation i found the length of each line :
A to B = sqrt(13)
B to C = sqrt(20)
D to C = sqrt(14)
A to D = sqrt(20)
What I did was divide it into 2 triangles find each hypotenuse and multiply it by each other
then divide it by 2. I don't know if there is a formula similar to this but the answer I got
was 16.748.
The problem I am having is to use the definition in the Relevant equation sections above.
How do I know which points would be a vector. If I know that then I can
probably figure about there Cross product and find its magnitude which is the parallelogram area.