What is the geometric interpretation of matrices A^{T}A and AA^{T}?

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In summary, the matrices A^{T}A and AA^{T} have various applications and interpretations in different contexts. Geometrically, A^{T}A can be thought of as a convex bilinear transformation or a length function on A(x), while AA^{T} can be seen as a metric induced on a manifold by its embedding in \mathbb{R}^N. They also have algebraic interpretations, such as being the inverse matrix for some groups and having uses in least squares.
  • #1
monea83
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The matrices [tex]A^{T}A[/tex] and [tex]AA^{T}[/tex] come up in a variety of contexts. How should one think about them - is there a way to understand them intuitively, e.g. do they have a geometric interpretation?
 
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  • #2
monea83 said:
The matrices [tex]A^{T}A[/tex] and [tex]AA^{T}[/tex] come up in a variety of contexts. How should one think about them - is there a way to understand them intuitively, e.g. do they have a geometric interpretation?

In general there is no real interpretation that comes to mind. With some specific groups the transpose matrix is actually the inverse matrix. Matrices that have this property include the rotation matrices that have a determinant of one.

Geometrically rotation matrices conserve length. So if you had a vector with the tail at the origin (in other words a point), then when you apply a rotation it preserves length of that vector: if you apply it to a set of points it preserves area/volume etc.

There are of course other uses for transpose matrices like least squares, but off the top of my head I can't give you geometric descriptions or interpretations for those.
 
  • #3
monea83 said:
is there a way to understand them intuitively,
Lots of practice. :smile:



One thing I intuit about them is that it is often the "right" thing to use when you might have used x2 in an analogous situation with real numbers, or used a norm with an analogous situation with a vector.

Also, you can think of them as being a way to turn a matrix into a symmetric, square matrix that does the "least damage" in some sense.

Of course, these are all algebraic ways to intuit them, rather than the geometric one you asked about. :frown:
 
  • #4
I think about it that way:

For n=3 for exemple,
Think at A as a linear transformation on R3: then you can think at A^T A as a convex bilinear transformation on R3xR3 giving you the scalar product of two vectors A(x1) and A(x2)

In particular, when x1 = x2 = x, I think at it as a "lengh" fonction on A(x) (hence positive defiinte)
 
  • #5
Its eigenvalues are the singular values of A. In the basis of the eigenvectors of A*A and AA*, the matrix A is 'almost' diagonal. This is the Singular value decomposition.

The Singular value decomposition has some geometric implications, but I don't know whether this qualifies as a geometric explanation of A*A itself.
 
  • #6
One thing from differential geometry comes to mind: If [tex] \gamma : \mathbb{R}^k \to \mathbb{R}^N [/tex] is a parametrization of a [tex] k [/tex]-manifold [tex] M \in \mathbb{R}^N [/tex], and [tex] A = [D\gamma] [/tex] is its Jacobian, then the matrix [tex] A^T A [/tex] is the metric induced on [tex] M [/tex] by the embedding in [tex] \mathbb{R}^N [/tex], which is a _very_ geometric object. This is just a reflection of the fact that [tex] A^T A [/tex] is the matrix of inner products of the columns of [tex] A [/tex] (which is a nice geometric interpretation in and of itself), and in our particular case, the columns of [tex] A [/tex] are the basis vectors of the tangent space to [tex] M [/tex] in the coordinates we've chosen. This fact sometimes comes up in slightly disguised form in the context of multivariable calculus, in the formula for the volume element of a manifold with parametrization [tex] \gamma [/tex]: [tex] dV_M = \sqrt{ [D\gamma]^T [D\gamma] } dV_k [/tex], where "[tex] dV_k [/tex]" is the volume element in [tex] \mathbb{R}^k [/tex]. Since [tex] A^T A [/tex] is the metric, this is just a version of the usual formula [tex] dV_M = \sqrt{g} dV_k [/tex], where [tex] g [/tex] is the determinant of the metric.
 

Related to What is the geometric interpretation of matrices A^{T}A and AA^{T}?

1. What is the meaning of A^T A and A A^T?

The notation A^T A represents the matrix multiplication of the transpose of matrix A with A. This results in a square matrix with the same number of rows and columns as the original matrix A. Similarly, A A^T represents the matrix multiplication of matrix A with its transpose, resulting in a square matrix with the same number of rows and columns as A.

2. What is the purpose of calculating A^T A and A A^T?

Calculating A^T A and A A^T is useful in linear algebra and statistics for performing various operations, such as finding inverses, solving systems of equations, and performing principal component analysis.

3. How do you interpret the results of A^T A and A A^T?

The resulting square matrix from A^T A and A A^T can provide insights into the structure and relationships of the original matrix A. For example, the diagonal elements of these matrices represent the sum of squares of the corresponding row or column in A, which can be useful for understanding the variability in the data.

4. What are the differences between A^T A and A A^T?

The main difference between A^T A and A A^T is the resulting matrix dimensions. A^T A results in a square matrix, while A A^T results in a rectangular matrix. Additionally, the order of multiplication affects the resulting values in the matrices, but both operations are commutative (A^T A = A A^T).

5. In what situations would you use A^T A and A A^T?

A^T A and A A^T are commonly used in linear algebra and statistics for various purposes, such as finding inverses, solving systems of equations, and performing principal component analysis. They can also be used for data preprocessing and feature extraction in machine learning and data analysis tasks.

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