- #1
likephysics
- 636
- 2
For a BJT with voltage divider bias (but without emitter deneration resistor), what is the beta dependence?
Ib is (Vth-Vbe)/Rth [where, Vth and Rth are thevenin equivalent of the divider)
Ic = β * Ib
The above is almost same as just base bias, where a resistor from base is collected to supply.
The design guideline is usually, the current flowing thru the divider should be 10x the base current. How does that help in this case?
Ib is (Vth-Vbe)/Rth [where, Vth and Rth are thevenin equivalent of the divider)
Ic = β * Ib
The above is almost same as just base bias, where a resistor from base is collected to supply.
The design guideline is usually, the current flowing thru the divider should be 10x the base current. How does that help in this case?