- #1
BroIIy
- 6
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Hello, this is my 1st time asking a question. May I have some assistance?
I will just copy and paste the question so that I don't mess up anything
A single-turn circular loop of radius 0.08 m and resistance 6 is coaxial with a solenoid of length 90 cm and a radius of 0.04 m, with 1950 turns. A variable resistor, as indicated in Fig. 30-37, is varied in such a way that the solenoid current falls linearly from 5 A to 1.4 A in 0.3 sec.
link==> http://www.photodump.com/BroIIy/30-37fig.html <==
Figure 30-37
(a) What is the induced current in the loop?
not really sure, if I did know I could solve it.
R1 = .08
Resistance = 6
L = .9
R2 = .04
N = 1950
I1 = 5
I2 = 1.4
T = .3
u_o = 4*pi*10^-7
I3 = E / Resistance
E = (Bf - Bo) * A / T (Bf = Magnetic field final, && Bo = Magnetic field initial)
this is where it gets confusing for me
Bf = u_o * N * I2 / L ?
Bo = ?
A = pi * R1^2 ?
is any of this even in the right direction?
Thank you for your time.
I will just copy and paste the question so that I don't mess up anything
Homework Statement
A single-turn circular loop of radius 0.08 m and resistance 6 is coaxial with a solenoid of length 90 cm and a radius of 0.04 m, with 1950 turns. A variable resistor, as indicated in Fig. 30-37, is varied in such a way that the solenoid current falls linearly from 5 A to 1.4 A in 0.3 sec.
link==> http://www.photodump.com/BroIIy/30-37fig.html <==
Figure 30-37
(a) What is the induced current in the loop?
Homework Equations
not really sure, if I did know I could solve it.
The Attempt at a Solution
R1 = .08
Resistance = 6
L = .9
R2 = .04
N = 1950
I1 = 5
I2 = 1.4
T = .3
u_o = 4*pi*10^-7
I3 = E / Resistance
E = (Bf - Bo) * A / T (Bf = Magnetic field final, && Bo = Magnetic field initial)
this is where it gets confusing for me
Bf = u_o * N * I2 / L ?
Bo = ?
A = pi * R1^2 ?
is any of this even in the right direction?
Thank you for your time.
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