- #1
Radarithm
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Homework Statement
A stone is thrown horizontally from a height h above the ground (h > 0). The stone hits the ground after having traveled a horizontal distance x (x > 0). What is the expression for the initial speed v of the stone? Neglect air resistance. (please use the variables x and h and the constant g in your answer)
Homework Equations
h = h0+v0y sin([itex]\theta[/itex])×t+½at2
x = x0+v0x cos([itex]\theta[/itex])×t+½at2
v2x = v20x + 2a(x - x0)
v2h = v20h + 2a(x - x0)
The Attempt at a Solution
The velocity when x = 0 (after the rock hits the ground) is 0, so I used that as v in the 3rd equation. a is simply -g (gravity). After simplifying these two I got: v0x = [itex]\sqrt{2gx}[/itex] and v0h = [itex]\sqrt{2gx}[/itex]
I am obviously doing something wrong; I can't find a way to relate h, x , and g to find v0. Any help would be appreciated.
edit: x0 is equal to 0.