- #1
Boltzman Oscillation
- 233
- 26
So the classical law of force given by Newton is F= ma = dp/dt = qE. Thus if i integrate the last two equivalents I get:
∫(dp/dt)dt = q∫Edt
p + C = q∫Edt
correct?
then what would the integral of energy be? I know that E = P/t. I guess I could let P = VI = I^2 * R = (dq/dt)^2 *R eerrr then E = (dq/dt)^2 *R/t and
p + C = qR∫(dq/dt)^2 / t dt
am i getting somewhere or not? I am just curious to see what integrating E can get me in relationship to momentum. Thanks
∫(dp/dt)dt = q∫Edt
p + C = q∫Edt
correct?
then what would the integral of energy be? I know that E = P/t. I guess I could let P = VI = I^2 * R = (dq/dt)^2 *R eerrr then E = (dq/dt)^2 *R/t and
p + C = qR∫(dq/dt)^2 / t dt
am i getting somewhere or not? I am just curious to see what integrating E can get me in relationship to momentum. Thanks