- #1
phillyolly said:So, first, I would like to show that E intersects with F in 0.
Since E= -1>=x>=0 and F E= 0>=x>=1, these two intervals overlap only in 0.
phillyolly said:Answering your questions,
(E intersect F)=N/A,
f(E intersect F)=N/A,
f(E) will still be equal f(F),
And the last question is tricky for me.
The work in the attached file in post 5 looks pretty good, but post 7, which came later, has some errors, so I'm not so sure the OP has it quite yet.Raskolnikov said:Mark44, that was a typo on his part. Look at his work in the latest attached thumbnail and his posts since then. He's got it pretty much now I think.
A subset in real analysis refers to a set that contains elements that are also contained in another set. For example, if set A contains the elements {1, 2, 3} and set B contains the elements {2, 3}, then set B is a subset of set A.
To determine if a set is a subset of another set in real analysis, you need to check if all the elements of the first set are also present in the second set. If this is true, then the first set is a subset of the second set.
A proper subset is a subset that contains fewer elements than the original set, while an improper subset contains the same elements as the original set. For example, if set A contains the elements {1, 2, 3} and set B contains the elements {1, 2}, then set B is a proper subset of set A, while set A is an improper subset of itself.
Yes, a set can be a subset of itself in real analysis. This is known as an improper subset, as the set contains all the elements of itself.
Subsets are closely related to other concepts in real analysis, such as supersets, intersections, and unions. These concepts are used to manipulate and compare sets to better understand their properties and relationships. For example, the intersection of two sets results in a subset that contains only the elements that are common to both sets.