What is the Inverse Laplace Transform of Y(s) = (1/τs+1)(1/s)?

[Pietair]

Homework Statement

Take the Inverse Laplace Transform of: Y(s)=\frac{1}{\tau s+1}\cdot \frac{1}{s}

2. The attempt at a solution
I know:
L^{-1}(\frac{1}{\tau s+1})=\frac{1}{\tau}e^{\frac{-t}{\tau}}
and:
L^{-1}({\frac{1}{s}})=1

But how to continue?

 

[LCKurtz]

Factor tau out of the denominator of the first fraction in Y(s) and use partial fraction expansion to break Y(s) into the sum of two simple fractions.

 

[Pietair]

Awesome, thanks a lot!