You dropped a very important factor of three in going from y=ln(x^3-3x^2+3x-1) to x=ln(y^3-y^2+3y-1).tg43fly said:y=ln(x^3-3x^2+3x-1)
x=ln(y^3-y^2+3y-1)
e^x=(y^3-y^2+3y-1)
Those factors of three should suggest something. Hint:Look at Pascal's triangle.i looked around for inverse of cubic functions and i found a monster of a formula:
http://www.math.vanderbilt.edu/~schectex/courses/cubic/
i really hope i missed something to find the inverse
An inverse for a cubic function is a function that can reverse the effects of the original cubic function. It is also known as the inverse cubic function.
To find the inverse for a cubic function, you can follow these steps:
1. Write the cubic function in the form of y = ax^3 + bx^2 + cx + d.
2. Replace y with x and x with y.
3. Solve for y.
4. The resulting equation is the inverse for the cubic function.
The domain of an inverse cubic function is the range of the original cubic function, and the range of an inverse cubic function is the domain of the original cubic function.
An inverse cubic function is the reflection of the original cubic function over the line y = x. This means that the input and output values of the two functions are switched.
Understanding inverse for cubic functions can help in solving complex problems involving cubic functions. It can also be useful in graphing and analyzing cubic functions, as well as in real-life applications such as engineering and physics.