- #1
BilgeRat
- 2
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Greetings all. I was solicited by a friend to find the inverse of a particular function, and I can't for the life of me determine/remember how.
The original equation is
y = 3+x^2+tan((1/2)*Pi*x)
with x on (-1,1).
The function is invertible - f' is always > 0 on that interval - but I have had no success attempting to determine precisely what the inverse is.
Thanks for any help you can give.
The original equation is
y = 3+x^2+tan((1/2)*Pi*x)
with x on (-1,1).
The function is invertible - f' is always > 0 on that interval - but I have had no success attempting to determine precisely what the inverse is.
Thanks for any help you can give.