- #36
Baluncore
Science Advisor
2023 Award
- 15,078
- 8,937
I really don't think there is a problem with the magnitude of the current.TonyStewart said:These problems can be found simply by looking what fails when so much power is being pumped by examining the impedance and energy (heat) in every part with limits on peak and RMS current specs.
L = 10 uH; V = 12 volt; f = 300 kHz; Duty = 30%.
Tcycle = 3.333 usec; Ton = 1 usec; Toff = 2.333 usec.
When the switch closes, the inductor is connected across the 12 V supply.
V = L·di/dt; ∴ di/dt = V/L = 12 V / 10 uH = 1.2 amp per microsecond.
With a 1 mA load current, it will take almost 1 msec for the output to rise to about 160 volts.