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Mark44 said:|sin(t)| = sin(t) on [0, pi], and |sin(t)| = -sin(t) on [pi, 2pi] or on [-pi, 0]
Ah of course, thanks :)vela said:Think geometric series where r=exp(-pi*s).
The Laplace transform of |sint| is 1/(1+s^2), where s is the complex variable.
The Laplace transform of |sint| is important because it allows us to solve differential equations involving absolute values, which are commonly encountered in engineering and physics problems.
The Laplace transform of |sint| is used in a variety of real-world applications, such as in the analysis of electrical circuits, control systems, and signal processing.
No, the Laplace transform of |sint| is not a one-to-one function. Different functions can have the same Laplace transform, making it more of a many-to-one relationship.
Yes, the Laplace transform of |sint| can be inverted using the inverse Laplace transform, which converts the function back to its original form in the time domain.