- #1
Blackwolf189
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A stream of water is shot with an initial speed of 2.3 m/s at a beetle on a leaf 3cm above the waters surface. If the fish aims in such a way that the stream of water is moving horizontally when it hits the beetle what is the launch angle.
Given:
Because the stream is moving horizontally then Vy = 0 m/s.
Ay = -9.8 m/s (gravity)
Displacement y (Dy) = 3 cm
Initial V = 2.3 m/s
How can i find the launch angle
Dy = Initial Vy * Time + 1/2(Ay)* Time*Time but don't know time or Vy
and i know nothing for x.
Given:
Because the stream is moving horizontally then Vy = 0 m/s.
Ay = -9.8 m/s (gravity)
Displacement y (Dy) = 3 cm
Initial V = 2.3 m/s
How can i find the launch angle
Dy = Initial Vy * Time + 1/2(Ay)* Time*Time but don't know time or Vy
and i know nothing for x.