What Is the Launch Angle of a Ball Thrown Against a Wall?

[richpetty888]

Homework Statement

A ball is thrown with initial velocity 20m/sec against a wall 50 meters away. It is released from a height of 1.8 meters, and hits the wall at 1.2 meters. Find the angle of the throw.

Homework Equations

50=20t*cos(theta)
-.6=20t*sin(theta)-.5(9.8)(t^2)

The Attempt at a Solution

Is it possible to solve this problem without knowing t(time between launch and hitting the wall)? Thanks for the help, I need to know if I'm missing a formula or something.

 

[Pheo1986]

im not 100% sure about this but you don't need to find t, you just need to rearange your 1st equatoin so you have t=... and then substitute that into your 2nd equation and then you can find theta. maybe

 

[kerimek]

I would respond that it is not possible to solve this problem without knowing the time (t) between launch and hitting the wall. In order to calculate the angle of the throw, we need to know the time, as it is a variable in both equations provided. Without this information, we cannot accurately determine the angle of the throw. It is important to have all necessary information in order to solve a problem accurately and effectively. I would recommend reviewing the problem and checking if there is any other information given that could help determine the time. If not, it may be necessary to ask for clarification or additional information in order to solve the problem.