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Homework Statement
A wood cylinder of mass m = 0.250 kg and length L = 0.100 m with N =10 turns of wire wrapped around it longitudinally, so that the plane of the wire coil contains the long axis of the cylinder. The cylinder is released on a plane inclined at an angle theta to the horizontal, with the plane of the coil parallel to the incline plane. If there is a vertical uniform magnetic field of magnitude 0.5T, what is the least current i through the coil that keeps the cylinder from rolling down the plane?
Homework Equations
force = NiL x B
The Attempt at a Solution
The answer is 2.45A, i try to find all the forces and solve when torque is zero, but i can't elimate the sin theta or cos theta thing. Please help, thankyou.
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