What is the least value of the sum $|p-1|+|p-2|+\cdots+|p-10|$?

[anemone]

Determine the least value of the sum $|p-1|+|p-2|+\cdots+|p-10|$ where $p \in R$.

 

[Amer]

Nice question, here is a solution

Spoiler

I think p=5.5

|------|------|------|------|--\/--|------|------|------|------|
1...2...3...4...5.,5.5,..6...7...8...9...10

The sum equal in this case 9+7+5+3+1 = 25

 

[mente oscura]

Determine the least value of the sum $|p-1|+|p-2|+\cdots+|p-10|$ where $p \in R$.

Hello.

Spoiler

by symmetry:

If it were 9 elements:

$$4+3+2+1+0+|-1|+|-2|+|-3|+|-4|=20$$

Is now equivalent to insert "5" or "- 5"

Solution: $$p \in{ } [6,5]$$

Regards.

 

[lfdahl]

Spoiler

$Let \; \; S(p) = \sum_{i=1}^{10}\left | p-i \right |= \sum_{i=1}^{10}\sqrt{(p-i)^2} \\\\ S'(p)= \sum_{i=1}^{10}\frac{(p-i)}{|p-i|}= (\pm) 1(\pm) 1...(\pm) 1$,
where each sign depends on the sign of the difference: $p-i$.
The minimal sum requires: $S'(p)=0$, which happens when the signed ones annihilate:

$\sum_{i=1}^{10} (\pm )1 = 0.$ (Therefore, the case $p=i$ is not of interest here)

Thus, there must be exactly five $+1$ and five $-1$. Therefore $p$ is the midpoint between $5$ and $6$

And the minimal sum is: $S_{min}=2*(5*5.5-15)=25$.

 

[anemone]

Thank you so much for participating, guys! :)

Solution taken from other intelligent mind:
[FONT=MathJax_Main]|[/FONT]

Spoiler

Note that $|p-m|+|p-(11-m)| \ge 11-2m$. If we are to add the inequalities for $m=1,\,2,\,3,\,4,\,5$, we get $|p-1|+|p-2|+\cdots+|p-9|+|p-10| \ge 55-2(1+2+3+4+5)=25$, hence, the least value of the specified sum is 25.