- #1
karush
Gold Member
MHB
- 3,269
- 5
\tiny{s8.1.6.64}
Evaluate
$\displaystyle\lim_{x \to 2}
\dfrac{\sqrt{6-x}{-2}}{\sqrt{3-x}-1}$
ok so if you plug in 2 directly you get $\dfrac{0}{0}$
So we either use L'H rule or use conjugate
or is there better way
Evaluate
$\displaystyle\lim_{x \to 2}
\dfrac{\sqrt{6-x}{-2}}{\sqrt{3-x}-1}$
ok so if you plug in 2 directly you get $\dfrac{0}{0}$
So we either use L'H rule or use conjugate
or is there better way