- #1
khurram usman
- 87
- 0
limit x-->1 of [sqrt(x-1)]
i know that for limit to be defined the left and right handed limits should be equal.
in the above problem, the left handed limit is undefined because it is the square rot of a negative no. but i checked this question on alphawolfram.com and also on MATHEMATICA . both the programs were giving limit as 0
so i supposed i was missing something but when i submitted my answer as 'undefined' it was marked as correct and i was given full credit
so please everyone clarify this problem
and also consider this one: lim x-->1 of sqrt[1-x]
in this case the right hand liit is not defined but again mathematica gave the same answer '0'
i know that for limit to be defined the left and right handed limits should be equal.
in the above problem, the left handed limit is undefined because it is the square rot of a negative no. but i checked this question on alphawolfram.com and also on MATHEMATICA . both the programs were giving limit as 0
so i supposed i was missing something but when i submitted my answer as 'undefined' it was marked as correct and i was given full credit
so please everyone clarify this problem
and also consider this one: lim x-->1 of sqrt[1-x]
in this case the right hand liit is not defined but again mathematica gave the same answer '0'