What is the magnitude of the force?

In summary, Mike is pulling a train consisting of a locomotive and two rail cars with masses of 2.00 x 10^4 kg and 0.50 x 10^4 kg, respectively, using a rope. The train is accelerating at 0.045 m/s^2 and the question asks for the magnitude of the force in the coupling between the locomotive and first car. Using the equation F=ma and drawing a free body diagram, it can be determined that the force at the front of the first car is equal to the force at the back of the last car, which is responsible for accelerating the train. This force can be calculated using the given acceleration and mass of the last car.
  • #1
nmi13
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Homework Statement


Mike is training for a strongman competition. Using a rope, Mike is pulling a locomotive of mass 2.00 x 10^4 kg coupled to two 0.50 x10^4 kg rail cars. Mike causes the train to accelerate at 0.045 m/s^2 . What is the magnitude of the force in the coupling between the locomotive and first car?[/B]
Mass of locomotive = 2.00*10^4 kg
Mass of each rail cars = 0.5*10^4 kg
acceleration = 0.045m/s^2

Homework Equations


F= ma

The Attempt at a Solution


I just don't know exactly how to begin to answer this question. I am unable to find any similar questions to help me out with. A nudge in the right direction is all I need. Thank you!
 
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  • #2
nmi13 said:

Homework Statement


Mike is training for a strongman competition. Using a rope, Mike is pulling a locomotive of mass 2.00 x 10^4 kg coupled to two 0.50 x10^4 kg rail cars. Mike causes the train to accelerate at 0.045 m/s^2 . What is the magnitude of the force in the coupling between the locomotive and first car?[/B]
Mass of locomotive = 2.00*10^4 kg
Mass of each rail cars = 0.5*10^4 kg
acceleration = 0.045m/s^2

Homework Equations


F= ma

The Attempt at a Solution


I just don't know exactly how to begin to answer this question. I am unable to find any similar questions to help me out with. A nudge in the right direction is all I need. Thank you!

Draw a free body diagram for the rail cars. I.e for the last car, there is a net force pulling the car forward such that the acceleration of the last car is 0.045 m/s^2. What is that force? That force is equal and opposite the force at the back of the first car, pulling back. At the front of the first car, there is also a force pulling it forward. The net force on the first car is such that the first car is accelerating at 0.045 m/s^2. What is the force at the front of the first car?
 

FAQ: What is the magnitude of the force?

What is the definition of magnitude in terms of force?

Magnitude is a measure of the strength or intensity of a force. It is a scalar quantity that represents the size or amount of the force without considering its direction.

How is the magnitude of a force calculated?

The magnitude of a force can be calculated using the equation F = ma, where F is the force, m is the mass of the object, and a is the acceleration. Another way to calculate magnitude is by using the formula F = kx, where k is the spring constant and x is the displacement from the equilibrium position.

What is the difference between magnitude and direction in terms of force?

Magnitude refers to the size or strength of a force, while direction refers to the path or line along which the force is acting. Both magnitude and direction are important in fully understanding a force vector.

Can the magnitude of a force be negative?

No, the magnitude of a force is always positive. Negative values can be used to indicate the direction of a force, but magnitude is always a positive value.

How does the magnitude of a force affect the motion of an object?

The magnitude of a force determines the acceleration of an object. The greater the magnitude of the force, the greater the acceleration will be. This is described by Newton's second law, which states that the acceleration of an object is directly proportional to the magnitude of the net force acting on it.

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