What is the magnitude of the net force acting on the ball?

In summary, the given problems deal with force, acceleration and distance, and work and energy. Remember to properly convert units and use relevant formulas to solve for the unknown values.
  • #1
jandominic145
30
0
1)When a 58 g tennis ball is served, it accelerates from rest to a speed of 45 m/s. The impact with the racket gives the ball a constant acceleration over a distance of 44 cm. What is the magnitude of the net force acting on the ball?

2)A skater with an initial speed of 7.60 m/s is gliding across the ice. Air resistance is negligible. (a) The coefficient of kinetic friction between the ice and the skate blades is 0.100. Find the deceleration casued by kinetic friction. (b) How far will the skater travel before coming to rest?

Forces and Newton's Laws of Motion
please give me a given and formula

answer at the back book
1) 130N
2) a) 0.980 b) 29.5 m
 
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  • #2
attempt the problems first then tell me which part u having trouble with
 
  • #3
ralilu said:
attempt the problems first then tell me which part u having trouble with

Forces and Newton's Laws of Motion
please give me a given and formula

answer at the back book
1) 130N
2) a) 0.980 b) 29.5 m
 
  • #4
thats not really attempting the problem

here are a few hints:

question 1) find the acceleration and multiply it by the mass
2) do they tell u the mass of the sk8er? u need the mass to work out the kinetic friction
 
  • #5
nevermind, for question 2 u don't need the mass:

calculate decceleration: final velocity squared= initial velocity squared + 2as
work done = change in kinetic energy = force x distance the mass will cancel out
 
  • #6
ralilu said:
nevermind, for question 2 u don't need the mass:

calculate decceleration: final velocity squared= initial velocity squared + 2as
work done = change in kinetic energy = force x distance the mass will cancel out

tnx for your helping me
 
  • #7
These are both questions dealing with work and energy. A kinematic perspective will suffice as well, since we're dealing with constant accelerations, but the understanding you should be striving for is one of work and energy.

Consider the initial and final energies for both cases, and consider the forces performing work on the tennis ball, and skier, respectively.

For the tennis ball, the work is the average net force, times the distance over which it acted. (Remember proper unit conversions!)

For the skater, draw an FBD, and remember that rearranging Newton's second law provides us with: [tex]\vec a = \frac{\vec F}{m}[/tex]
And again remember that the work of the net force is equal to the change in kinetic energy (Work-energy theorem) [tex]W= \bar Fd=\Delta E_k[/tex]
 

Related to What is the magnitude of the net force acting on the ball?

1. What is net force?

Net force is the overall force acting on an object. It is the vector sum of all the forces acting on the object, taking into account both magnitude and direction.

2. How do you calculate net force?

To calculate the net force on an object, you must add up all the individual forces acting on the object. If the forces are acting in the same direction, you simply add their magnitudes. If the forces are acting in opposite directions, you subtract the smaller magnitude from the larger one.

3. What is the unit of measurement for net force?

The unit of measurement for net force is Newtons (N). 1 Newton is equal to 1 kilogram meter per second squared (kg*m/s^2).

4. How does net force affect an object's motion?

According to Newton's Second Law of Motion, the net force acting on an object is directly proportional to the acceleration of the object. This means that a larger net force will result in a greater acceleration, and a smaller net force will result in a smaller acceleration.

5. Can the net force on an object ever be zero?

Yes, the net force on an object can be zero if all the individual forces acting on the object cancel each other out. This can happen if the forces are equal in magnitude and opposite in direction, resulting in a net force of zero.

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