What is the marble's speed at the top?

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In summary, the conversation discusses questions regarding the speed and compression of objects in motion. The first question involves a marble spinning in a horizontal pipe, while the second question involves a vertical spring. The conversation provides equations and methods for finding the answers, including trigonometry for the first question and considering energy for the second question. The conversation also addresses the possible influence of rotational inertia and friction in the first question.
  • #1
kw_cecilia
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I am doing these questions, and I don't quite understand.

1. A marble spins in a verticle plane around the inside of a smooth, 20cm-diameter horizontal pipe. The marble's speed at the bottom of the circle is 3.0m/s

a) what is the marble's speed at the top?
b) Find an algebraic expression for hte marble's speed when it is at angle phata, where the angle is measured from the bottom of the circle.

For part a, I used

1/2mvf^2 + mgyf = 1/2 mvi^2 + mgyi

to find vf , and i got 2.25 m/s

But for part b, i don't understand where should I draw the angle.

2. A vertical spring with k = 490 N/m is standing on the ground. You are holding a 5.0kg block just above the spring, not quite touching it.

a) How far does the spring compress if you let go of the block suddendly?
b) How far does the spring compress if you slowly lower the block to the point where you can remove your hand without disturbing it?
c) Why are your two answers different?

How do I deal with questions with a vertical spring?
 
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  • #2
Hi,

If I am reading you question right...

For the fist part:

Draw a circle then draw a vertical radius from the centre to the base. Now draw any radius from the centre to another part of the circumference. The angle between the two is the angle required.

Use the same equations as before, but use trig to find the the height.

For the second part:

his spring will compress rather than extend. The equations/method is exactly the same as for extension springs but now x as in "F=kx" is the compression from the natural length, not the extension!

Hope that helps

EaGG
 
  • #3
Oo.. thankyou! Now I understand the first part !
But for the second part, does it mean the mg of block = kx?
 
  • #4
Sorry not to get back...bit busy!

mg = kx ...yes for lowering slowly..but for the "dropping" part consider the energies involved at the top and bottom.

EaGG
 
  • #5
Sorry, I didn't quite understand the answer for -1-. Does it take into account the rotational inertia of the marble? They would need to give us the mass and size of the marble in order for that to be taken into account, though.
 
  • #6
I don't believe that the marble is spinning about a diametrical axis. The pipe is smooth and there is no friction involved. It's just "sliding".
 

FAQ: What is the marble's speed at the top?

What is the definition of speed?

Speed is a measure of how fast an object is moving. It is typically measured in units of distance per time, such as meters per second or miles per hour.

How is the speed of an object calculated?

The speed of an object can be calculated by dividing the distance traveled by the time it took to travel that distance. This is known as the average speed formula: speed = distance/time.

What is the difference between speed and velocity?

Speed and velocity are often used interchangeably, but they have different meanings. Speed is a measure of how fast an object is moving, while velocity is a measure of both speed and direction.

How does the speed of an object change at different points during its motion?

The speed of an object can change at different points during its motion due to factors such as acceleration, deceleration, and changes in direction. For example, an object may have a higher speed when it is moving downhill compared to when it is moving uphill.

How can the speed of a marble at the top be determined?

The speed of a marble at the top can be determined by measuring the distance it traveled and the time it took to reach the top. This information can then be used to calculate the average speed of the marble using the formula speed = distance/time.

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