- #1
jmb07
- 27
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Average molecular mass of air is 29 u. What is the mass density of air at 1 atm and -50 degrees celsius??
This is what i have so far...
V=(NkT)/P so V= [(29u)(1.38E^-23)(-50 + 273)]/ 1 = 8.9 x10^-20
The mass is equal to 29u x (6.022 x 10^23) =1.75 x 10^25
density =m/v so = 1.96 x 10^44...and that is wayyyy off! The correct answer is like around 1, 2, or 3...i need some help. What am i doing wrong?
This is what i have so far...
V=(NkT)/P so V= [(29u)(1.38E^-23)(-50 + 273)]/ 1 = 8.9 x10^-20
The mass is equal to 29u x (6.022 x 10^23) =1.75 x 10^25
density =m/v so = 1.96 x 10^44...and that is wayyyy off! The correct answer is like around 1, 2, or 3...i need some help. What am i doing wrong?