What Is the Mass of the Second Particle and the Magnitude of the Charges?

In summary, two equally charged particles held 3.2*10^(-3)m apart and released from rest experience initial accelerations of 7 m/s^2 and 9 m/s^2, respectively. Using Newton's third law and the equation F = q1q2 /r^2, the mass of the second particle is equal to m2 = m1(a1/a2) = 4.914*10^(-7) kg and the magnitude of the charge for each particle is equal to q1 = q2 = (m1a1^2) / (k(r^2)) = 1.244*10^-17 C.
  • #1
Saladsamurai
3,020
7

Homework Statement


Two equally charged particles are held 3.2*10^(-3)m apart and released from rest. The initial acceleration of the first is 7 m/s^2 and that of the second is 9 m/s^2.

If the mass of the first is m1= 6.3*10^(-7) kg, what are a) the mass of the second particle and b) the magnitude of the charge of each?



Homework Equations



F=ma
F=kq1q2/r^2


The Attempt at a Solution



I just need a kick in the right direction here. I am looking at a worked solution to the first part and they make the assumption

F1=F2 , thus, m1a1=m2a2

But, for some reason I am uneasy with this. Why are these two forces equal?

Sorry for the lame question... I am out of practice and am trying to do some review.

Thanks
 
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  • #2
Saladsamurai said:

Homework Statement


Two equally charged particles are held 3.2*10^(-3)m apart and released from rest. The initial acceleration of the first is 7 m/s^2 and that of the second is 9 m/s^2.

If the mass of the first is m1= 6.3*10^(-7) kg, what are a) the mass of the second particle and b) the magnitude of the charge of each?



Homework Equations



F=ma
F=kq1q2/r^2


The Attempt at a Solution



I just need a kick in the right direction here. I am looking at a worked solution to the first part and they make the assumption

F1=F2 , thus, m1a1=m2a2

But, for some reason I am uneasy with this. Why are these two forces equal?

Sorry for the lame question... I am out of practice and am trying to do some review.

Thanks
They form an action-reaction pair (Newton's third law). They must be equal!
 
  • #3
F = q1q2 /r^2

q1q2 is the same for both particles, as is r.
 
  • #4
nrqed said:
They form an action-reaction pair (Newton's third law). They must be equal!

I guess I can live with that.
 

FAQ: What Is the Mass of the Second Particle and the Magnitude of the Charges?

What is Coulomb's Law?

Coulomb's Law is a fundamental law in physics that describes the force of attraction or repulsion between two charged particles. It states that the force is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.

What does Coulomb's Law explain?

Coulomb's Law explains the behavior of electric charges and the forces between them. It helps to understand how charged particles interact and how electric fields are formed.

What is the equation for Coulomb's Law?

The equation for Coulomb's Law is F = k * (q1 * q2) / r^2, where F is the force between two charged particles, q1 and q2 are the magnitudes of the charges, r is the distance between them, and k is the Coulomb constant.

How is Coulomb's Law related to Newton's Law of Universal Gravitation?

Coulomb's Law and Newton's Law of Universal Gravitation are mathematically similar as they both involve an inverse square relationship between two quantities (distance for Coulomb's Law and distance squared for Newton's Law). However, they explain different types of forces - Coulomb's Law describes electrostatic forces between charged particles, while Newton's Law describes gravitational forces between massive bodies.

In what units is Coulomb's Law measured?

Coulomb's Law is measured in newtons (N) for force, coulombs (C) for charge, and meters (m) for distance. The Coulomb constant, k, has a value of approximately 9 x 10^9 Nm^2/C^2.

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