What is the mass of this car based on given forces?

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    Car Mass
In summary, the car has a 2000 N [west] driving force, and a total of 16000 N [down], due to the force of all 4 wheels.
  • #1
Ace.
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Homework Statement



Each of the four wheels of a car pushes on the road with a force of 4.0 x 103 N [down]. The driving force on the car is 8.0 x 103 N [west]. The frictional resistance on the car is 6.0 x 103 N [east]. Calculate the mass of the car.

Homework Equations



F = ma
Fnet = F1 + F2


The Attempt at a Solution



Fnet = F1 + F2
Fnet = FA - Ff
= 8.0 x 103 - 6.0 x 103
= 2000 N [west]​

Total force of all four wheels:
(4.0 x 103 N [down]) x 4
= 16000 N [down]​

FN = 16000 N[up]
But this is only part of the Normal Force, because the rest is coming from the weight of the car.

It seems to me that there isn't enough info to find mass?
 
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  • #2
Wait, is the normal force simply the force of all the wheels ?
 
  • #3
Ace. said:

Homework Statement



Each of the four wheels of a car pushes on the road with a force of 4.0 x 103 N [down]. The driving force on the car is 8.0 x 103 N [west]. The frictional resistance on the car is 6.0 x 103 N [east]. Calculate the mass of the car.

Homework Equations



F = ma
Fnet = F1 + F2


The Attempt at a Solution



Fnet = F1 + F2
Fnet = FA - Ff
= 8.0 x 103 - 6.0 x 103
= 2000 N [west]​

Total force of all four wheels:
(4.0 x 103 N [down]) x 4
= 16000 N [down]​

FN = 16000 N[up]
But this is only part of the Normal Force, because the rest is coming from the weight of the car.

It seems to me that there isn't enough info to find mass?

Ace. said:
Wait, is the normal force simply the force of all the wheels ?

That would be my answer. The horizontal movement forces in this case would not seem to affect the vertical weight.
 
  • #4
Actually, it looks from the sum of the horizontal forces that the car is accelerating, which will unbalance the weight on the front and back tires, but the sum of all 4 should be the same as at rest, I would think.

Hmm, need to think more about that...
 
  • #5

Based on the given information, we can calculate the net force acting on the car, but we cannot determine the mass without knowing the acceleration of the car. The equation F = ma requires knowledge of both force and acceleration to solve for mass. Therefore, we would need additional information, such as the acceleration or velocity of the car, to accurately calculate the mass. Alternatively, if we assume a constant velocity (zero acceleration), then the mass of the car would be equal to the ratio of the net force to the acceleration (which would be 0 in this case). However, this would not be an accurate representation of the true mass of the car.
 

Related to What is the mass of this car based on given forces?

1. How do you find the mass of a car?

To find the mass of a car, you can use a scale or weigh the car using a weight balance. Most cars have their mass listed in the owner's manual or on a sticker on the driver's side door.

2. What is the unit of measurement for car mass?

The unit of measurement for car mass is usually kilograms (kg) or pounds (lbs). Some countries may use different units such as tons or metric tons.

3. Does the mass of a car affect its performance?

Yes, the mass of a car can affect its performance. A heavier car will require more energy to accelerate and may have slower acceleration and lower fuel efficiency. However, a heavier car may also have better stability and handling at higher speeds.

4. Can you determine the mass of a car without weighing it?

Yes, you can estimate the mass of a car by using its dimensions and the density of the materials it is made of. However, this method may not be as accurate as actually weighing the car.

5. How does the mass of a car affect its safety?

The mass of a car can affect its safety in a number of ways. A heavier car may provide better protection in a crash due to its increased momentum, but it may also require a longer stopping distance. On the other hand, a lighter car may have better maneuverability and handling, but may be more vulnerable in a collision.

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