- #1
nooobie
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Homework Statement
find the greatest current through the capacitor with a capacitance of C=1.33uF, where the applied voltage is given by V = 250t^2 - 200t^3 volts.
Homework Equations
i = C(dV/dt)
The Attempt at a Solution
so i take the derivative of V:V'= 500t-600t^2...
and find values for time and i get
0= 100t(5 - 6t)
then t = 0, and 5/6.
testing these values in the second derivative V" = 500-1200t...I find 5/6 to be maximum...
plugging into the equation for i = (1.33*10^(-6))(500(5/6) - 600(5/6)^2)
which equates to zero...bah, this can be right...what am i doing wrong...am i taking the wrong derivative or something