Fusilli_Jerry89 said:well first i drew it and came up with:
F-127-71+42.6=50a for the wagon and concluded that an extra 4.6 N must be directed down the slope in order to move the box. I am clueless now.
EthanB said:Sum the forces on the block in one free-body diagram, then sum the forces on the cart in another.
There should be no force of friction acting up the ramp on the wagon. The wagon's motion is upwards, and friction resists the direction of motion.
Once we have four equations from summing our forces, find a way to relate the maximum static friction between the block and cart to the force being applied to the cart. Plug in the maximum friction and get the maximum force.
Fusilli_Jerry89 said:What I don't get is how can you supply extra Newtons downwards without actually touch the box? The force of friction stays the same, this has to do with inertia but I have no idea how to solve for this? Maybe I missed something in Physics last year, could anyone help?
The Box Sliding Wagon problem is a classic physics problem that involves a box resting on a frictionless, horizontal surface and attached to a wagon. The wagon is initially at rest, and when a force is applied to the wagon, it starts moving with the box on top of it. The question is, what happens to the box when the wagon stops?
The Box Sliding Wagon problem involves principles of Newton's Laws of Motion, specifically the first and second laws. The first law states that an object at rest will remain at rest unless acted upon by an external force, and an object in motion will remain in motion with a constant velocity unless acted upon by an external force. The second law states that the net force on an object is equal to the mass of the object multiplied by its acceleration.
Friction plays a crucial role in the Box Sliding Wagon problem. In the real world, there is no such thing as a perfectly frictionless surface, so in this problem, we assume that the surface has no friction. However, the box and wagon are still in contact with each other, creating a frictional force. This force acts in the opposite direction of the motion and can affect the acceleration and final position of the box on the wagon.
The equation used to solve the Box Sliding Wagon problem is F = ma, where F is the net force, m is the mass of the box, and a is the acceleration. This equation allows us to calculate the force and acceleration acting on the box and wagon system and determine the resulting motion.
The Box Sliding Wagon problem has real-world applications in the design of transportation systems, such as trains and roller coasters. It also has applications in understanding the motion of objects on inclined planes and the effects of friction. Additionally, the principles involved in this problem are essential in the development of technologies such as self-driving cars and robotics.