What is the maximum height a weighted spring can reach?

In summary, the problem involves a spring hanging from the ceiling with a ball of mass m and radius r attached to the other end. The system is in equilibrium with the spring having a constant k and natural length l0. The goal is to determine how far the ball needs to be pulled down from the equilibrium position for it to reach a distance d from the ceiling, without considering dampening forces. The equations involved are x0 = -mg/k, F = k(x-x0)-mg, K.E = 0 at (x0+x1) and d, and both P.E (G.P.E and E.P.E) are maximum at these points. To solve the problem, the potential energy at the bottom (where the ball
  • #1
arjwilliams
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Homework Statement


A spring is fixed at one end to the ceiling, with an ball of mass, m, and radius, r, hanging vertically at the other end of the spring. The system is in equilibrium. The spring has constant, k, and natural length, l0.

I then pull the ball down to an extension, x1, from the equilibrium position, x0. How far will I have to pull the ball down for the ball to reach a distance, d, from the ceiling, ignoring dampening forces?

g = acceleration by gravity
x = extension at any time

Homework Equations


x0 = -mg/k
F = k(x-x0) - mg
K.E = 0 at (x0 + x1) and d
both P.E (G.P.E and E.P.E) are maximum at these points.
K.E = 0.5*m*v^2 (where v is velocity of ball)
G.P.E = m*g*(x0 + x)
E.P.E = 0.5*k*x^2
any others

The Attempt at a Solution


No idea where to start.
 
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  • #2
Try to set the potential energy at the bottom (where the ball is released) to the potential energy at the very top.
 

FAQ: What is the maximum height a weighted spring can reach?

What is the definition of "Max Height of Weighted Spring"?

The max height of a weighted spring refers to the highest point that the spring reaches when it is released and allowed to bounce freely under the influence of gravity.

How is the max height of a weighted spring calculated?

The max height of a weighted spring can be calculated using the equation H = (kx^2)/(2mg), where H is the max height, k is the spring constant, x is the amplitude of the oscillation, m is the mass of the weight, and g is the acceleration due to gravity.

What factors can affect the max height of a weighted spring?

The max height of a weighted spring can be affected by the spring's elasticity, the mass of the weight attached to the spring, the initial amplitude of the oscillation, and the strength of gravity.

Can the max height of a weighted spring be greater than the initial amplitude?

Yes, the max height of a weighted spring can be greater than the initial amplitude if the spring has enough energy and the weight is heavy enough to overcome the force of gravity.

How can the max height of a weighted spring be increased?

The max height of a weighted spring can be increased by increasing the spring constant, increasing the initial amplitude of the oscillation, or increasing the mass of the weight attached to the spring.

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