- #1
drawar
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Homework Statement
What is the maximum kinetic energy (in eV) of a photoelectron emitted when a surface, whose work function is 5eV, is illuminated by photons whose wavelength is 400 nm
1. -1.89
2. 1.89
3. 0
4. 3.1
Homework Equations
hc/(lambda)=work function + KE max
The Attempt at a Solution
After plugging numbers in the formula above, I get KE max=-1.89 eV, but I guess I must have done something wrong, since energy cannot be negative.