What is the meaning of a zero of a polynomial and how is it determined?

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In summary, the remainder theorem states that when a polynomial P(x) is divided by (x-a), the remainder is equal to P(a). To determine if a number is a zero of a polynomial, we can either plug in that number for x and see if the resulting value is 0, or we can divide the polynomial by (x-a) and see if the remainder is 0. The quotient is the result of the division, while the remainder is the leftover value.
  • #1
duki
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Homework Statement



Determine the remainder using the remainder theorem
P(x) = 2x^3 + 3x^2 + 4x - 10; D(x) = x + 1

Homework Equations



Remainder Theorem

The Attempt at a Solution


x = -1
P(x) = -2 + 3 - 4 - 10
R -13Can you have a negative remainder?The next question says:
Decide whether or not the number is a zero of the polynomial.

Is that just another way of saying find the remainder?
 
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  • #2
Sure you can have a negative remainder. Is the 'number' you are referring to -1? If so, IS it a root?
 
  • #3
Oh ok, so -13 is the right answer to that one?


No, the next question is referring to a different polynomial, though the question was stated different. Can I use the remainder theorem again, or is it asking me to do something different?
 
  • #4
What's the remainder of x-r if r is a root? And if you don't believe -13 is the remainder - check it with a long division.
 
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  • #5
The remainder theorem which you mention but don't cite (that would have been a good idea) says that if P(x) is divided by (x-a) then the remainder is P(a). That's true because P(x)/(x-a)= Q(x)+ remainder r is the same as saying P(x)= (x-a)Q(x)+ r. What happens when you set x= a?
 
  • #6
I'm lost =/

My teacher didn't go over the theorem, he just told us how to use the f(x) = blah

Sorry I didn't site it.

I'll work it out in long division to see if I got the right answer, but I'm thinking I did since you can have a - remainder.

Now I'm not sure what to do about the question that asks if a certain number is a zero of the polynomial... is that the same as saying find the remainder?
 
  • #7
Look at what Halls said. Dividing a polynomial P(x) by (x-a) and getting a remainder r and a quotient Q(x) means you can write the polynomial P(x)=Q(x)*(x-a)+r, right? Make sense? Just the same as division by numbers? Putting x=a in that gives:

P(a)=r

since a-a=0. That is the Remainder theorem. So to see if r=0 (which is the same as saying that a is a root, yes?), you can either put 'a' into the polynomial and see if you get zero or you can divide the polynomial by (x-a) and see if the remainder is zero. Same thing. Do actually try out the long division to prove it to yourself.
 
  • #8
What is a?

When i divided it with long division I got -9 =/
But when i used synthetic division i got -13 again...

The question about finding a zero is

P(x) = -x^4 + 9x^2 - 9x + 27; 3
So I did used
P(3) = -(3)^4 + 9(3)^2 - 9(3) + 27 = 0
so yes it is a zero?

There is yet another problem that says find the quotient and remainder of the following problems and whatnot... i can get the remainder but how do i get the quotient?
Is that where I subtract a root from the equation since I just took one out?
If so here is what I did:

Problem: (3x^5 + 4x^4 + 2x^2 - 1) / (x + 2)

Solution (using synth div.)

3 -2 4 -6 R11
so
3x^3 - 2x^2 + 4x - 6 R11 ??
 
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  • #9
duki said:
1. Homework Statement

Determine the remainder using the remainder theorem
P(x) = 2x^3 + 3x^2 + 4x - 10; D(x) = x + 1

2. Homework Equations

Remainder Theorem

3. The Attempt at a Solution
x = -1
P(x) = -2 + 3 - 4 - 10
R -13
In the statement of the problem you said the the polynomial was 2x3+ 3x2+ 4x- 10. Here you use "-2 + 3 - 4 -10" which corresponds to -2x3+ 3x2- 4x- 10. Which is it?

The question about finding a zero is

P(x) = -x^4 + 9x^2 - 9x + 27; 3
So I did used
P(3) = -(3)^4 + 9(3)^2 - 9(3) + 27 = 0
so yes it is a zero?
? If you were asked to find a zero, where did you get "3" from? If you were asked to determine whether or not 3 is a zero then it's just a matter of understanding what a "zero" of a polynomial is.

There is yet another problem that says find the quotient and remainder of the following problems and whatnot... i can get the remainder but how do i get the quotient?
Is that where I subtract a root from the equation since I just took one out?
If so here is what I did:

Problem: (3x^5 + 4x^4 + 2x^2 - 1) / (x + 2)

Solution (using synth div.)

3 -2 4 -6 R11
so
3x^3 - 2x^2 + 4x - 6 R11 ??
Are you saying you do not know the meaning of the word "quotient"? If you were to divide 1233 by 5 what would be the quotient and what would be the remainder?
 
  • #10
In the statement of the problem you said the the polynomial was 2x3+ 3x2+ 4x- 10. Here you use "-2 + 3 - 4 -10" which corresponds to -2x3+ 3x2- 4x- 10. Which is it?

It's the one stated in the problem, but i did (-1)^3 * 2.

? If you were asked to find a zero, where did you get "3" from? If you were asked to determine whether or not 3 is a zero then it's just a matter of understanding what a "zero" of a polynomial is.

Yes, I needed to determine if 3 was a zero.

Are you saying you do not know the meaning of the word "quotient"? If you were to divide 1233 by 5 what would be the quotient and what would be the remainder?

I actually typed the problem wrong... but it's ok I have it right now.

thanks for the help.
 

FAQ: What is the meaning of a zero of a polynomial and how is it determined?

What is an equation of higher degree?

An equation of higher degree is an algebraic equation that involves variables raised to powers higher than one. The degree of an equation is determined by the highest exponent in the equation.

How do you solve equations of higher degree?

The method for solving equations of higher degree varies depending on the degree of the equation. Some common methods include factoring, using the quadratic formula, and completing the square. In some cases, numerical methods or graphing may be used to approximate solutions.

What is the difference between a polynomial equation and an equation of higher degree?

A polynomial equation is a type of equation that involves only variables, constants, and positive integer exponents. An equation of higher degree can be a polynomial equation, but it may also involve variables raised to negative exponents or irrational exponents.

Can equations of higher degree have more than one solution?

Yes, equations of higher degree can have multiple solutions. The number of solutions is determined by the degree of the equation. For example, a quadratic equation (degree 2) can have a maximum of two solutions.

What real-life applications use equations of higher degree?

Equations of higher degree are used in various fields such as physics, engineering, and economics to model real-world situations. For example, parabolic trajectories of objects in motion can be described using quadratic equations, while cubic equations can be used to model population growth.

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