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Homework Statement
A 18.6-kg box rests on a frictionless ramp with a 13.7° slope. The mover pulls on a rope attached to the box to pull it up the incline. If the rope makes an angle of 38.8° with the horizontal, what is the smallest force F the mover will have to exert to move the box up the ramp?
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http://img93.imageshack.us/img93/7287/4figure44alt.gif
Homework Equations
The Attempt at a Solution
[tex]\sum\vec{F}=ma[/tex]
[tex]\sum\vec{F}=0[/tex]
[tex]\sum\ F_{x}=0 => F_{x}-W_{x}=0[/tex]
[tex]\sum\ F_{y}=0[/tex]
I made a graph from the ramp model and found:
a=0
m=18.6 kg
θ=13.7°
σ=38.8°
B=25.1°
F=?
w=mg
[tex]F_{x}=F\cos{B}[/tex]
[tex]W_{x}=W\sin\theta[/tex]
[tex]F_{y}=F[/tex][tex]\sin[/tex][tex]B[/tex]
[tex]W_{y}=W\cos\theta[/tex]
I thought 18.6(9.81)sinθ would give me the answer but that wasn't correct.
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