What Is the Minimum Speed Needed for a Particle to Stay on a Rippled Surface?

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In summary, the equation h(x) = d Cos[k x] describes a rippled surface on which a particle is moving without friction. Gravity acts down in the negative direction. To stay on the surface at all times, the particle's speed in the x direction must be equal to or less than Sqrt[g/(k^2 d)]. The required speed at the crest of the wave can be found by considering the boundary conditions, as the particle will leave the surface at the point with the largest curvature. However, it is possible for the particle to leave at another point if it is going faster than the crest's maximum speed.
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yxgao
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Consider a particle moving without friction on a rippled surface, given by the equation h(x) = d Cos[k x]. Gravity acts down in the negative h direction. If the particle starts at x=0 with a speed in the x direction, for what value of v will the particle stay on the surface at all times?

The answer is if v<= Sqrt[g/(k^2 d)].

I found a general formula that involves x but is too complicated to solve. There must be another way to do this without using a calculator. Thanks!

Ying
 
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  • #2
Look at the boundary conditions.

The point where the the particle will leave the surface is the point with the largest curvature. You need to solve for the required speed at the crest of the wave, and it will hold for all other points on the wave.
 
  • #3
How do you know that the particle will leave the surface at the crest of the wave?
 
  • #4
At the crest, the centripetal acceleration needed to maintain contact is the highest.

It can leave at another point, but it has to be going faster than the crest's max speed to do so.
 

FAQ: What Is the Minimum Speed Needed for a Particle to Stay on a Rippled Surface?

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