What Is the Minimum Work to Withdraw a Magnetic Core?

In summary, the problem involves calculating the minimum work required to withdraw a core from a solenoid at constant temperature and current. This can be done by considering the change in free energy and entropy of the system, and using the Maxwell's equations for a magnetic system.
  • #1
Truecrimson
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Homework Statement



Please see P4, P5, and P6 in http://panda.unm.edu/pandaweb/graduate/prelims/SM_S09.pdf

"...What is the minimum work that must be performed to completely withdraw the core at constant I and T?"

Homework Equations


The Attempt at a Solution



I have no idea how to do this type of problems. But if I look at P5, using [tex]S=-\left(\frac{\partial F}{\partial T}\right)_V[/tex], given the free energy in P4, I get the answer for the case when the core is in the solenoid. So I guess that the free energy when the core is withdrawn is [tex]F=-\sigma TV\ln \frac{T}{T_0}[/tex]. Is it correct?

To increase free energy, one has to put in work. Since free energy limits the maximum amount of work that can be extracted from a system, it should also limit the minimum amount of work that can be done on the system to do something. Since the magnetic field tends to pull the core into the solenoid and decrease the core's energy by the term [tex]\frac{1}{2}\mu \eta^2 I^2 V[/tex] in the free energy, that is the minimum amount of work we have to put in. This is my interpretation of my guess.

Any hint or useful equations for P6?
 
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  • #2


Hi there,

Thank you for posting your question on the forum. The problem you are working on is related to the thermodynamics of a magnetic system, and it involves calculating the minimum work required to withdraw a core from a solenoid at constant temperature and current.

In order to solve this problem, we can start by considering the free energy expression given in P4: F = -\sigma TV\ln \frac{T}{T_0}. This expression is valid when the core is inside the solenoid. However, when the core is withdrawn, the magnetic field inside the solenoid will decrease, leading to a change in the free energy of the system. This change in free energy can be calculated using the Maxwell's equations for a magnetic system, which relate the magnetic field, current, and magnetic flux.

Using these equations, we can calculate the change in free energy as the core is withdrawn from the solenoid. This change in free energy corresponds to the minimum work that must be performed in order to withdraw the core at constant temperature and current. Therefore, the minimum work required is given by the change in free energy, which can be calculated using the Maxwell's equations.

As for P6, it involves calculating the change in entropy of the system as the core is withdrawn from the solenoid. This can be done by considering the change in the magnetic field and current, and using the expression for entropy given in P5: S=-\left(\frac{\partial F}{\partial T}\right)_V. By calculating the change in entropy, we can determine how the entropy of the system changes as the core is withdrawn, which can give us insights into the thermodynamics of the system.

I hope this helps. Good luck with your problem!
 

FAQ: What Is the Minimum Work to Withdraw a Magnetic Core?

What is the concept of "free energy" in a magnetic system?

The free energy of a magnetic system is a measure of the system's ability to do work or produce useful energy. It is the difference between the internal energy of the system and the energy that is lost to the surroundings due to entropy. In a magnetic system, free energy is determined by the orientation and strength of the magnetic field.

How is the free energy of a magnetic system calculated?

The free energy of a magnetic system is calculated using the formula F = U - TS, where F is the free energy, U is the internal energy, T is the temperature, and S is the entropy of the system. This formula takes into account the effects of both temperature and entropy on the system's free energy.

What factors affect the free energy of a magnetic system?

The free energy of a magnetic system is affected by several factors, including the strength and orientation of the magnetic field, the temperature, and the entropy of the system. Additionally, the type of material and the presence of any external forces can also impact the free energy of a magnetic system.

How does the free energy of a magnetic system relate to magnetization?

The free energy of a magnetic system is closely related to its magnetization. As the free energy decreases, the magnetization of the system increases. This is because a decrease in free energy indicates a more stable and ordered state, which is favorable for the alignment of magnetic moments and thus results in higher magnetization.

Can the free energy of a magnetic system be harnessed for practical use?

Yes, the free energy of a magnetic system can be harnessed for practical use. This is known as magnetic energy harvesting, where the energy from a magnetic field is converted into usable electrical energy. This technology is still in its early stages, but it has the potential to provide a sustainable source of energy in the future.

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