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tnutty
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Homework Statement
A missile's trajectory takes it to a maximum altitude of 1200 km.
If its launch speed is 6.2 km/s , how fast is it moving at the peak of its trajectory?
Homework Equations
K+U = K_o+U_o
U(r) = -GMm/r
The Attempt at a Solution
Alright some people have been telling me its zero. Intuitively that's what I thought, but
I guess its wrong. Nevertheless, here is my attempt :
K+U = K_o +U_o;
=
1/2mV^2 - GM_eM/r_d = 1/2mV_o^2 - GM_em / r_e
and solving for
V^2 = V_o^2 - 2GM_e/r_e + GM_e/r_d
where,
V_o = 6.2km -> 6.2*1000m
G = universal graity = 6.67*10^-11
M_e = mass of Earth = 5.98*10^24
r_e = radius of Earth = 6.37 * 10^6;
r_d = distance between the object and the center of earth
= 1200km -> 1200*1000m
and my answer is terms of meters
~2400m
so dividing by 1000
and
v_p ~ 24m/s