- #1
gwiber
- 5
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1. A 0.0097561 g quantity of an unknown gas occupies 0.2 L at 500 K and 2 atm. What is the Molecular Weight (MW) of the gas ?
2. PV = nRT
3. mw=0.0097561*0.082*500/2*0.2
mw=1
2. PV = nRT
3. mw=0.0097561*0.082*500/2*0.2
mw=1