What is the momentum at its maximum height?

[redhot209]

Homework Statement

What is its momentum halfway to its maximum height? Answer in units of kg m/s

A 0.12 kg ball of dough is thrown straight up into the air with an initial speed of 11 m/s. The acceleration of gravity is 9.8 m/s^2. What is the momentum at its maximum height? Answer in units of kg/ms. Answer is 0.

Homework Equations

tried to do 0.12x11/4.9 but was wrong.

The Attempt at a Solution

 

[heth]

What variables would you need to know to be able to calculate the momentum of an object?

(I think you probably already know this from your attempt, but it's always better to write out the equation you are using explicitly, then put numbers in. Doing this helps you spot what you actually need to do - which variables you already know and which you need to find out somehow.)

Then: how would you calculate each of these variables if you were doing a question that asked for values of each of the variables individually. (You may already have values for one or more of the variables.)

Once you've done that, you can put it back together.

 

[thomate1]

To answer this question, we first need to understand what momentum is. Momentum is the product of an object's mass and velocity, and it is a measure of its motion. In this case, the ball of dough has an initial momentum of 0.12 kg x 11 m/s = 1.32 kg m/s.

At its maximum height, the ball's velocity is 0 m/s, meaning its momentum is also 0 kg m/s. This is because momentum is a vector quantity, and the direction of the velocity at the maximum height is opposite to the direction of the initial velocity.

Halfway to its maximum height, the ball's velocity will be half of its initial velocity, which is 5.5 m/s. Therefore, its momentum will be 0.12 kg x 5.5 m/s = 0.66 kg m/s.

In conclusion, the momentum at its maximum height is 0 kg m/s, and the momentum halfway to its maximum height is 0.66 kg m/s. I hope this helps clarify the concept of momentum for you.