What Is the Momentum of a Ball at Its Maximum Height?

[KatieLynn]

Homework Statement

A 0.15kg ball of dough is thrown straight up into the air with an initial speed of 17 m/s. The acceleration due to gravity is 9.81 m/s^2. What is its momentum at its maximum height?

Homework Equations

momentum=mass X velocity

change in momentum= mass (FinalVelocity - InitialVelocity)

The Attempt at a Solution

momentum = (0.15)(VF - 17)

but there are two unknowns, I'm not even sure that's what the problem is asking for though...

 

[PhanthomJay]

Homework Statement

A 0.15kg ball of dough is thrown straight up into the air with an initial speed of 17 m/s. The acceleration due to gravity is 9.81 m/s^2. What is its momentum at its maximum height?

Homework Equations

momentum=mass X velocity

change in momentum= mass (FinalVelocity - InitialVelocity)

The Attempt at a Solution

momentum = (0.15)(VF - 17)

but there are two unknowns, I'm not even sure that's what the problem is asking for though...

In this and your previous momentum questions, you keep referencing 'change in momentum' in your relevant equations,yet the problems do not ask for momentum change, they just ask for momentum. In this problem, what is the velocity of the ball when it reaches its maximum height?

 

[ogb p]

I would first clarify what the problem is asking for. Is it asking for the momentum of the ball at its maximum height, or is it asking for the change in momentum as the ball reaches its maximum height? Once this is clarified, I would use the appropriate equation to solve for the desired value.

If the problem is asking for the momentum of the ball at its maximum height, then we can use the equation momentum = mass X velocity. At its maximum height, the ball's velocity will be 0 m/s, since it has reached the highest point in its trajectory and is about to start falling back down. Therefore, the momentum of the ball at its maximum height would be 0 kg*m/s.

If the problem is asking for the change in momentum as the ball reaches its maximum height, then we can use the equation change in momentum = mass (FinalVelocity - InitialVelocity). In this case, the final velocity would be 0 m/s and the initial velocity would be 17 m/s. Plugging these values into the equation, we get a change in momentum of -2.55 kg*m/s. This means that as the ball reaches its maximum height, its momentum decreases by 2.55 kg*m/s.

In conclusion, the momentum of the ball at its maximum height is 0 kg*m/s and the change in momentum as it reaches its maximum height is -2.55 kg*m/s. It is important to clarify what the problem is asking for and use the appropriate equations to solve for the desired values.