- #1
Derill03
- 63
- 0
define the natural domain and range for f(x,y) = 1/sqrt(x^2-y)
I get D= {(x,y)|x^2-y>0} same as saying y can not equal x^2
R= {(x,Y)|f>0}
can someone tell me if I've approached this correctly?
I get D= {(x,y)|x^2-y>0} same as saying y can not equal x^2
R= {(x,Y)|f>0}
can someone tell me if I've approached this correctly?